-200p^2+12000p=0

Solution for -200p^2+12000p=0 equation:

-200p^2+12000p=0

a = -200; b = 12000; c = 0;
Δ = b2-4ac
Δ = 120002-4·(-200)·0
Δ = 144000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144000000}=12000$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12000)-12000}{2*-200}=\frac{-24000}{-400}
=+60
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12000)+12000}{2*-200}=\frac{0}{-400}
=0
$